Transformation of Axes – EAMCET Previous Year Questions
Questions
1. Find the transformed equation of \(x\cos\theta + y\sin\theta = p\), when the axes are rotated through an angle \(\theta\).
[AP EAMCET 17-09-20_Shift-1]- 1. \(X = p\)
- 2. \(Y = p\)
- 3. \(X + Y = p\)
- 4. \(X - Y = p\)
2. If the axes are rotated through an angle \(45^{\circ}\), then the co-ordinates of the point \((4\sqrt{2}, -6\sqrt{2})\) in the new system are
[AP EAMCET 17-09-20_Shift-2]- 1. \((-10, -2)\)
- 2. \((-2, -10)\)
- 3. \((10, 10)\)
- 4. \((-2, 10)\)
3. When the origin is shifted to \((2,3)\) the transformed equation is \(x^{2} + 3xy - 2y^{2} + 17x - 7y - 11 = 0\), then the original equation of the curve is
[AP EAMCET 18-09-20_Shift-2]- 1. \(x^{2} - 2y^{2} - 3xy + 4x - y + 20 = 0\)
- 2. \(x^{2} - 2y^{2} + 3xy + 4x - y - 20 = 0\)
- 3. \(x^{2} - 2y^{2} - 3xy - 4x - y + 20 = 0\)
- 4. \(x^{2} - 2y^{2} - 3xy + 4x - y - 20 = 0\)
4. The point to which the origin should be shifted so that the equation \(y^{2} - 6y - 4x + 13 = 0\) is transformed in the form \(y^{2} + Ax = 0\) is
[AP EAMCET 21-09-20_Shift-1]- 1. \((3,1)\)
- 2. \((-1, -1)\)
- 3. \((1,3)\)
- 4. \((-1,3)\)
5. Find the coordinates of \(M\) in the original system if the point \(M\) changes to \((4,3)\) when the axes are rotated through an angle of \(135^{\circ}\).
[AP EAMCET 22-09-20_Shift-2]- 1. \(\left(\frac{-1}{2},\frac{7}{2}\right)\)
- 2. \(\left(\frac{1}{2},\frac{7}{2}\right)\)
- 3. \(\left(\frac{-1}{\sqrt{2}},\frac{7}{\sqrt{2}}\right)\)
- 4. \(\left(\frac{1}{\sqrt{2}},\frac{7}{\sqrt{2}}\right)\)
6. The point to which the origin should be shifted so that the equation \(y^{2} - 6y - 4x + 13 = 0\) will not contain term in \(y\) and the constant term, is
[AP EAMCET 23-09-20_Shift-1]- 1. \((1,1)\)
- 2. \((1,2)\)
- 3. \((2,1)\)
- 4. \((1,3)\)
7. Which of the following statement is false?
- 1. The area of a triangle is invariant under the translation of the Axes
- 2. The slope of a straight line is invariant under the translation of the Axes
- 3. The shifting of origin to another point, while changing the direction of the axes, is called translation of axes.
- 4. If \(f(x,y) = 0\) is transformed equation of a curve when the axes are translated to the point \((h,k)\) then the original equation of the curve is \(f(x - h, y - k) = 0\)
8. The transformed equation of \(3x^{2} - 4xy = r^{2}\) when the coordinate axes are rotated through an angle \(\tan^{-1}(2)\) is
[TS EAMCET 09-09-20_Shift-1]- 1. \(X^{2} - 4Y^{2} = r^{2}\)
- 2. \(2XY + r^{2} = 0\)
- 3. \(4Y^{2} - X^{2} = r^{2}\)
- 4. \(XY = r^{2}\)
9. By shifting the origin to the point \((2,3)\) and then rotating the coordinate axes through an angle \(\theta\) in the counter clockwise direction, if the equation \(3x^{2} + 2xy + 3y^{2} - 18x - 22y + 50 = 0\) is transformed to \(4X^{2} + 2Y^{2} - 1 = 0\), then the angle \(\theta =\)
[TS EAMCET 09-09-20_Shift-2]- 1. \(\frac{\pi}{6}\)
- 2. \(\frac{\pi}{2}\)
- 3. \(\frac{\pi}{4}\)
- 4. \(\frac{\pi}{3}\)
10. When the origin is shifted to the point \(\left(\frac{3}{2},\frac{3}{2}\right)\) by the translation of coordinate axes, then the transformed equation of \(32x^{2} + 8xy + 32y^{2} - 108x - 108y + 99 = 0\) is
[TS EAMCET 10-09-20_Shift-1]- 1. \(72X^{2} + 56Y^{2} - 63 = 0\)
- 2. \(X^{2} - 14XY - 7Y^{2} - 2 = 0\)
- 3. \(32X^{2} - 16XY + 32Y^{2} - 225 = 0\)
- 4. \(32X^{2} + 8XY + 32Y^{2} - 63 = 0\)
11. The point \((4,1)\) undergoes the following transformations successively:
(i) reflection in the line \(x - y = 0\)
(ii) shifting through a distance of 2 units along the positive X-axis
(iii) projection on X-axis
- 1. \((3,4)\)
- 2. \((4,3)\)
- 3. \((3,0)\)
- 4. \((4,0)\)
12. Let C be a curve \(ax^{2} + 2hxy + by^{2} + 2gx + 2fy + c = 0\) in a Cartesian plane, by rotating the coordinate axes through an angle \(\frac{\pi}{4}\) in the positive direction, if the transformed equation of C is \(Y^{2} + XY - X = 0\), then \((h^{2} - ab) - 2gf =\)
[TS EAMCET 11-09-20_Shift-1]- 1. 0
- 2. 2
- 3. 1
- 4. -1
13. When the coordinate axes are rotated through an angle \(\theta\) in anticlockwise direction, if the transformed equation of \(x^{2} + y^{2} + 2xy + 2x + 6y + 1 = 0\) is \((2 + \sqrt{3})X^{2} + 2XY + (2 - \sqrt{3})Y^{2} + aX + bY + 2 = 0\), then \(3a - b =\)
[TS EAMCET 11-09-20_Shift-2]- 1. 10
- 2. \(2(1 + 2\sqrt{3})\)
- 3. 20
- 4. \(2(3 + \sqrt{3})\)
14. If the axes are rotated through an angle \(45^{\circ}\), the coordinates of the point \((2\sqrt{2}, -3\sqrt{2})\) in the new system are
[AP EAMCET 19-08-2021_Shift-1]- 1. \((3\sqrt{3}, -5)\)
- 2. \((-1, -5)\)
- 3. \((5\sqrt{3}, -7)\)
- 4. \((7, -\sqrt{3})\)
15. When the coordinate axes are rotated through an angle \(135^{\circ}\), the coordinates of a point P in the new system are known to be \((4, -3)\). Then find the coordinates of P in the original system.
[AP EAMCET 19-08-2021_Shift-2]- 1. \(\left(\frac{1}{\sqrt{2}},\frac{7}{\sqrt{2}}\right)\)
- 2. \(\left(\frac{-1}{\sqrt{2}},\frac{7}{\sqrt{2}}\right)\)
- 3. \(\left(\frac{1}{\sqrt{2}},\frac{-7}{\sqrt{2}}\right)\)
- 4. \(\left(\frac{-1}{\sqrt{2}},\frac{-7}{\sqrt{2}}\right)\)
16. When the axes are rotated through an angle \(45^{\circ}\), the new coordinates of a point P are \((1, -1)\). The coordinates of P in the original system are
[AP EAMCET 20-08-2021_Shift-1]- 1. \((\sqrt{2},\sqrt{2})\)
- 2. \((\sqrt{2},0)\)
- 3. \((0,\sqrt{2})\)
- 4. \((-\sqrt{2},0)\)
17. The point to which the origin should be shifted in order to eliminate the x and y terms from the equation \(9x^{2} + 4y^{2} + 10x + 12y + 1 = 0\) is
[AP EAMCET 20-08-2021_Shift-2]- 1. \(\left(\frac{5}{9},\frac{3}{2}\right)\)
- 2. \(\left(\frac{-5}{2},\frac{-3}{9}\right)\)
- 3. \(\left(\frac{-5}{9},\frac{-3}{2}\right)\)
- 4. \(\left(\frac{-3}{2},\frac{-5}{9}\right)\)
18. The transformed equation \(3x^{2} + 3y^{2} + 2xy = 2\) when the coordinate axes are rotated through an angle \(45^{\circ}\) is
[AP EAMCET 23-08-2021_Shift-1]- 1. \(x^{2} + 2y^{2} = 1\)
- 2. \(2x^{2} + y^{2} = 1\)
- 3. \(x^{2} + y^{2} = 1\)
- 4. \(x^{2} + 3y^{2} = 1\)
19. If a square ABCD where \(A(0,0), B(2,0), C(2,2), D(0,2)\) undergoes the following transformations successively, then the final figure would be a
(i) \(f_{1}(x,y)\to (y,x)\)
(ii) \(f_{2}(x,y)\to (x + 3y,y)\)
(iii) \(f_{3}(x,y)\to \left(\frac{x - y}{2},\frac{x + y}{2}\right)\)
- 1. Square
- 2. Rhombus
- 3. Rectangle
- 4. Parallelogram
20. Find the transformed equation of the curve \(x^{2} + 2\sqrt{3}xy - y^{2} = 8\) when the axes are rotated through an angle \(\frac{\pi}{3}\).
[AP EAMCET 24-08-2021_Shift-2]- 1. \(x^{2} + y^{2} + 2\sqrt{3}xy = 8\)
- 2. \(x^{2} + y^{2} - 2\sqrt{3}xy = 8\)
- 3. \(x^{2} - y^{2} + 2\sqrt{3}xy = 8\)
- 4. \(x^{2} - y^{2} - 2\sqrt{3}xy = 8\)
21. The equation obtained by transforming \(x^{2} + y^{2} - 6x + 10y - 2 = 0\) to the parallel axis through \((3, -5)\) is
[AP EAMCET 25-08-2021_Shift-1]- 1. \(x^{2} + y^{2} = 16\)
- 2. \(x^{2} + y^{2} = 9\)
- 3. \(x^{2} + y^{2} = 25\)
- 4. \(x^{2} + y^{2} = 36\)
22. If the axes are transformed to the point \((-1,1)\) then the equation \(3x^{2} + y^{2} + 2x + 4y + 15 = 0\) would transform to
[AP EAMCET 25-08-2021_Shift-2]- 1. \(3x^{2} + 2y^{2} - 4x + 6y + 23 = 0\)
- 2. \(3x^{2} + y^{2} - 4x + 6y + 21 = 0\)
- 3. \(3x^{2} + y^{2} + 4x - 6y - 21 = 0\)
- 4. \(3x^{2} + y^{2} + 4x + 6y + 21 = 0\)
23. If \(P(a,b)\) is the point to which the origin is to be shifted by translation of axes so as to remove the first degree terms from the equation \(4x^{2} + 2xy + y^{2} - 8x - 4y - 12 = 0\) and \(\theta\) is the angle through which the axes are to be rotated about the origin so as to remove the xy-term from the above equation, then \(a + b + 3\tan 2\theta =\)
[TS EAMCET 04-08-2021_Shift-2]- 1. 2
- 2. 4
- 3. 8
- 4. 6
24. The transformed equation of the curve \(2x^{2} + y^{2} - 3x + 5y - 8 = 0\) translated to the point \((-1,2)\) is
[TS EAMCET 04-08-2021_Shift-1]- 1. \(2x^{2} + y^{2} - 7x + 9y + 11 = 0\)
- 2. \(2x^{2} + y^{2} + 7x + 9y + 11 = 0\)
- 3. \(2x^{2} + y^{2} - x + y + 11 = 0\)
- 4. \(2x^{2} + y^{2} + 7x - 9y + 11 = 0\)
25. When the origin is shifted to \((-1,2)\) by the translation of axes, the transformed equation of \(x^{2} + y^{2} + 2x - 4y + 1 = 0\) is
[TS EAMCET 05-08-2021_Shift-1]- 1. \(X^{2} + Y^{2} = 4\)
- 2. \(X^{2} + Y^{2} = 16\)
- 3. \(X^{2} + 2X + Y^{2} = 4\)
- 4. \(X^{2} - 2X + Y^{2} = 16\)
26. The angle by which axes are to be rotated without changing the origin so that the transformed equation of \(x^{2} + 4xy - y^{2} = 0\) in new coordinates \((X,Y)\) does not contain XY term is
[TS EAMCET 05-08-2021_Shift-2]- 1. \(\frac{1}{2}\tan^{-1}(2)\)
- 2. \(\tan^{-1}(2)\)
- 3. \(\frac{\pi}{8}\)
- 4. \(\frac{\pi}{4}\)
27. The equation of a curve \(C\) is transformed to \(X^{2} + Y^{2} - 6X + 8Y + 21 = 0\) by the rotation of coordinate axes about the origin through an angle of \(\frac{\pi}{4}\) in the positive direction of X-axis. If \(ax^{2} + by^{2} + cx + dy + e = 0\) is the equation of the curve \(C\) before the transformation, then \((a + b + c^{2} + d^{2} - 5e)^{2} =\)
[TS EAMCET 06-08-2021_Shift-2]- 1. 4
- 2. 9
- 3. 16
- 4. 25
28. If the coordinate axes are rotated in positive direction by \(45^{\circ}\) without changing the origin, then the transformed equation of \(3x^{2} + 3y^{2} + 2xy - 2 = 0\) is
[TS EAMCET 06-08-2021_Shift-1]- 1. \(2X^{2} + Y^{2} = 1\)
- 2. \(X^{2} + 2Y^{2} = 1\)
- 3. \(X^{2} - 2Y^{2} = 1\)
- 4. \(2X^{2} - Y^{2} = 1\)
29. When the coordinate axes are rotated about the origin in the positive direction through an angle \(\frac{\pi}{4}\), if the equation \(49x^{2} + 25y^{2} = 1225\) is transformed to \(px^{2} + qxy + ry^{2} = t\) and the G.C.D of \(p,q,r,t\) is 1, then
[TS EAMCET 18-07-2022_Shift-1]- 1. \((p - q + r - 32)^{2} = 4t\)
- 2. \((p - q - r + 12)^{2} = t\)
- 3. \((p + q + r - 15)^{2} = t\)
- 4. \((p - q - r + 13)^{2} = t\)
30. The transformed equation of \(3x^{2} + 4xy + y^{2} - 8x - 4y - 4 = 0\) is \(f(X,Y) = aX^{2} + 2hXY + bY^{2} + c = 0\) by translation of axes. Then \(f(1,1) =\)
[TS EAMCET 18-07-2022_Shift-2]- 1. 0
- 2. 1
- 3. -1
- 4. -8
31. The point to which the origin is to be shifted by translation of axes so that the transformed equation of \(y^{2} + 4y + 8x - 2 = 0\) will not contain \(y\) term and constant term is
[TS EAMCET 19-07-2022_Shift-1]- 1. \(\left(\frac{3}{4}, -2\right)\)
- 2. \(\left(\frac{-3}{4}, -2\right)\)
- 3. \(\left(2,\frac{3}{4}\right)\)
- 4. \(\left(-2, - \frac{3}{4}\right)\)
32. If \(x^{2} = 8ay\) is the transformed equation of \(x^{2} - 4y + 6x + 15 = 0\) when the origin is shifted to the point \((\alpha ,\beta)\) by translation of axes, then \(2\alpha +8\beta^{2} =\)
[TS EAMCET 19-07-2022_Shift-2]- 1. 8
- 2. 18
- 3. 12
- 4. 16
33. By rotating the axes through an angle of \(30^{0}\) in the anti-clockwise direction about the origin, the equation \(4x^{2} + 12xy + 9y^{2} + 6x + 9y + 2 = 0\) becomes \(ax^{2} + 2hxy + by^{2} + 2gx + 2fy + c = 0\), then
[TS EAMCET 20-07-2022_Shift-2]- 1. \(a = 21 - 6\sqrt{3}\)
- 2. \(g / f = \frac{3 + 2\sqrt{3}}{3\sqrt{3} - 2}\)
- 3. \(b = 31 + 6\sqrt{3}\)
- 4. \(c = 6\)
34. The transformed equation of \(2x^{2} + 3y^{2} - z^{2} - 8x + 18y + 2z + 9 = 0\) when the axes are translated to the point \((2, - 3, 1)\) is
[18th May 2023 Shift-1]- 1. \(2x^{2} + 3y^{2} - z^{2} = 25\)
- 2. \(2x^{2} + 3y^{2} + z^{2} = 25\)
- 3. \(2x^{2} - 3y^{2} - z^{2} = 25\)
- 4. \(2x^{2} + 3y^{2} - z^{2} = 50\)
35. The angle by which the coordinate axes are to be rotated about the origin so that the transformed equation of \(\sqrt{3} x^{2} + \left(\sqrt{3} - 1\right)xy - y^{2} = 0\) would be free from \(xy\) term is
[12th May 2023 Shift-1]- 1. \(45^{\circ}\)
- 2. \(22.5^{\circ}\)
- 3. \(15^{\circ}\)
- 4. \(7.5^{\circ}\)
36. Let P be the point to which origin has to be shifted by the translation of axes so as to remove the first degree terms from the equation \(3x^{2} + y^{2} - 6x + 4y + 4 = 0\). If the origin is shifted to P by the translation of axes, then the transformed equation of \(2x^{2} + 3xy - 5y^{2} + 2x - 23y - 24 = 0\) is
[13th May 2023 Shift-1]- 1. \(x^{2} + 4xy - 3y^{2} - 4x + 20y + 23 = 0\)
- 2. \(2x^{2} - 3xy + 5y^{2} = 0\)
- 3. \(2x^{2} + 3xy - 5y^{2} = 0\)
- 4. \(2x^{2} + 3xy - 5y^{2} - 13 = 0\)
37. When the origin is shifted to the point \((h,k)\) by translating the coordinate axes, the equation \(S\equiv 2x^{2} - xy + y^{2} + 2x + 3y + 1 = 0\) is changed to \(S^{1}\equiv ax^{2} + 2hxy + by^{2} - 3 = 0\). Again by rotating the coordinate axes about the new origin through the angle \(\theta\) in the positive direction, \(S^{1} = 0\) is changed to \(Ax^{2} + By^{2} + C = 0\). Then \(h + k + \tan 2\theta =\)
[EAPCET 13-05-23 Shift-2]- 1. -4
- 2. 0
- 3. 1
- 4. -1
| Q.No | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 | 19 | 20 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| Ans | 1 | 2 | 2 | 3 | 3 | 4 | 3 | 3 | 3 | 4 | 3 | 1 | 3 | 2 | 2 | 2 | 3 | 2 | 4 | 4 |
| Q.No | 21 | 22 | 23 | 24 | 25 | 26 | 27 | 28 | 29 | 30 | 31 | 32 | 33 | 34 | 35 | 36 | 37 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| Ans | 4 | 2 | 2 | 1 | 1 | 1 | 2 | 1 | 3 | 1 | 1 | 3 | 2 | 1 | 4 | 3 | 1 |